x^2=24+20x

Solution for x^2=24+20x equation:

x^2=24+20x

We move all terms to the left:

x^2-(24+20x)=0

We add all the numbers together, and all the variables

x^2-(20x+24)=0

We get rid of parentheses

x^2-20x-24=0

a = 1; b = -20; c = -24;
Δ = b2-4ac
Δ = -202-4·1·(-24)
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{31}}{2*1}=\frac{20-4\sqrt{31}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{31}}{2*1}=\frac{20+4\sqrt{31}}{2}
$